Sebastian Baez advanced to the Round of 64 at the 2026 ATP Indian Wells with a commanding 6-3, 6-2 victory over Hsin Tseng Chun on Thursday. The Argentine capitalized on 33 unforced errors from his opponent and converted three of nine break point opportunities to close out the match in straight sets.
Chun struggled to find any rhythm on serve, dropping five double faults and winning just 24% of second serve points. Baez, by contrast, dominated when his first serve landed, winning 78% of those points. The difference was starkest on return: Baez broke serve three times while never facing a single break point converted against him. Chun’s winner count of just six—compared to 14 for Baez—underscored his inability to dictate play on the hard courts.
The second set slipped away quickly for Chun as errors compounded. Baez, steady rather than spectacular, closed out the win with minimal fuss to set up a second-round clash.
Key Takeaways
- Baez’s return game proved decisive, converting 3 of 9 break points while Chun failed to convert any of his 3 opportunities.
- Chun’s 33 unforced errors—nearly double Baez’s 19—gift-wrapped the match for the Argentine, who won 14 winners to Chun’s mere 6.
- The second serve discrepancy was glaring: Baez won 42% of points on his second delivery compared to Chun’s dismal 24%.
- Despite neither player hitting an ace, Baez’s superior first serve effectiveness (78% points won vs 62%) gave him control throughout.
Player Analysis
Sebastian Baez
Baez produced a textbook performance for an opening-round match, managing the contest with minimal risk. His 78% win rate on first serve points kept Chun at arm’s length, and while his second serve wasn’t dominant—winning just 42% of those points—it didn’t need to be. The key was his discipline: 19 unforced errors against 14 winners suggests he stayed within himself and let his opponent self-destruct. Converting three breaks from nine chances wasn’t spectacular efficiency, but against an overmatched opponent, it was more than enough. Baez never faced a break point, a testament to how little pressure Chun could generate.
Hsin Tseng Chun
Chun’s performance bordered on the woeful. Five double faults and 33 unforced errors tell the story of a player unable to settle into the match. Winning just 24% of second serve points is catastrophic at this level—it meant nearly every time Baez forced a second serve, he was in position to attack. The winner count of six across two sets reveals Chun’s inability to construct points or apply pressure. He created three break point opportunities but squandered all of them, a microcosm of a forgettable afternoon in the California desert. The hard courts of Indian Wells offered him no refuge.
Match Statistics
| Sebastian Baez | Stat | Hsin Tseng Chun |
|---|---|---|
| 1 | Double Faults | 5 |
| 77% | 1st Serve % | 71% |
| 78% | 1st Serve Points Won | 62% |
| 42% | 2nd Serve Points Won | 24% |
| 3/9 | Break Points Won | 0/3 |
| 14 | Winners | 6 |
| 19 | Unforced Errors | 33 |
| 62 | Total Points Won | 41 |
Frequently Asked Questions
What was the final score of Sebastian Baez vs Hsin Tseng Chun at Indian Wells 2026?
Sebastian Baez defeated Hsin Tseng Chun 6-3, 6-2 in the Round of 128 at the 2026 ATP Indian Wells tournament.
How many unforced errors did Hsin Tseng Chun commit against Sebastian Baez?
Hsin Tseng Chun committed 33 unforced errors compared to just 6 winners, a major factor in his straight-sets loss.
How many break points did Sebastian Baez convert at Indian Wells?
Baez converted 3 of 9 break point opportunities, while Chun failed to convert any of his 3 chances.
What was Sebastian Baez’s first serve win percentage against Chun?
Baez won 78% of first serve points compared to Chun’s 62%, giving him a significant advantage throughout the match.
What’s Next
Baez advances to the Round of 64, where he will look to build on this routine victory and extend his run at Indian Wells.
Follow all results: ATP Indian Wells 2026.
Head-to-head history: Hsin Tseng Chun vs Sebastian Baez.
